Hi this is a simple and very good question on probability. Just need to think differently to answer this question.
Posting this for your reference.
Q) As a part of a game, four people each much secretly chose an integer between
1 and 4 inclusive. What is the approximate likelihood that all four people will
chose different numbers?
Soln: The probability that the first person will pick unique number is 1 (obviously)
then the probability for the second is 3/4 since one number is already picked by the
first, then similarly the probabilities for the 3rd and 4th are 1/2 and 1/4 respectively.
Their product 3/4*1/2*1/4 = 3/32
Posting this for your reference.
Q) As a part of a game, four people each much secretly chose an integer between
1 and 4 inclusive. What is the approximate likelihood that all four people will
chose different numbers?
Soln: The probability that the first person will pick unique number is 1 (obviously)
then the probability for the second is 3/4 since one number is already picked by the
first, then similarly the probabilities for the 3rd and 4th are 1/2 and 1/4 respectively.
Their product 3/4*1/2*1/4 = 3/32
