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Signs, Roots, and Cubes (Inequalities)

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Source: — Data Sufficiency |
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by selango » Mon Jul 26, 2010 5:54 pm
Can you please check the question again?
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by sandi10017 » Mon Jul 26, 2010 7:02 pm
Sorry - I didn't realize the square root sign was eliminated from my cut and paste. Eitherway, the full question is below.


Is x > y?

(1) sq rt (x) > y

(2) x3 > y
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by selango » Mon Jul 26, 2010 7:29 pm
x>y?

stmt1,

sqrt(x)>y

x=16,y=2,x>y

x=1/4,y=1/3,x<y

Insufficient

stmt2,

x^3>y

x=2,y=1,x>y

x=2,y=3,x<Y

Insufficient

Combining 1 and 2,

x cannot be -ve as sqrt(x) wont hold.x cannot be fraction as stmt1 fails.

If x is 0, then y has to be negative to satisfy both.X>Y

If x>0 both statements are satisfied.

Pick C
Last edited by selango on Mon Jul 26, 2010 9:09 pm, edited 1 time in total.
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by Asif » Mon Jul 26, 2010 8:51 pm
I think its E.

2^3>4

in this case

x<y
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by selango » Mon Jul 26, 2010 9:10 pm
My mistake...Edited the post..Answer is C
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by outreach » Tue Jul 27, 2010 12:48 am
Asif wrote:I think its E.

2^3>4

in this case

x<y
but x=2 and y=4
does not satisfy stmt1 and stmt2
hence it has to be C
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