[(0.03)^2 + (0.11)^2 + (0.013)^2 ] / [ (0.003)^2 + (0.011)^2 + (0.0013)^2 ] = ? (A) 0.01 (B)0.1 (C)1 (D)10 (E)100

harsh.champ wrote:[(0.03)^2 + (0.11)^2 + (0.013)^2 ] / [ (0.003)^2 + (0.011)^2 + (0.0013)^2 ] = ? (A) 0.01 (B)0.1 (C)1 (D)10 (E)100 I f u see the question carefully each term in denominator is a multiple of (0.1)^2 if we take the common out numerator and denominator becomes same. so Ans = 1/(0.1)^2 =100 Ans E

Why don't you two just trade private messages since you two only reply to each other's threads?

osirus0830 wrote:Why don't you two just trade private messages since you two only reply to each other's threads? Osirus I think the question was posted by harsh.champ at 5:52 pm and I replied it at 12:46 am . So You had approx 7 hrs to post the solution . If you don't post the solution someone will have to answer it...why to be so panic... I don't think question was so tough that you cannot solve it....so why to blame others..

shashank.ism wrote:osirus0830 wrote:Why don't you two just trade private messages since you two only reply to each other's threads? Osirus I think the question was posted by harsh at 5:52 pm and I am reply it at 12:46 am . So You had approx 7 hrs to post the solution . If you don't post the solution someone will have to answer it...why to be so panic... I don't think question was so tough that you cannot solve it....so why to blame others.. You are a worthless cheating troll. Everyone knows you two are cheating. Its ok, those of us that actually add value to this board have a plan, enjoy your cheating, we are going to make it very difficult for you to get a prize