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Source: — Data Sufficiency |
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by sbasha » Sun Aug 30, 2009 9:37 am
IMO C

E only =60 (stmt 1)
G only =0
S only =70 (given)

none = 20 (stmt 2)
ES = x
EG = x
GS = x
EGS = 0 (stem)

Just need to get ES+GS+EG (subtract from 200)
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by pathaniaus » Sun Aug 30, 2009 12:16 pm
sbasha wrote:IMO C

E only =60 (stmt 1)
G only =0
S only =70 (given)

none = 20 (stmt 2)
ES = x
EG = x
GS = x
EGS = 0 (stem)

Just need to get ES+GS+EG (subtract from 200)
could you explain this in more detail please?
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by tienvunguyen » Mon Aug 31, 2009 8:54 am
The question is rather ambiguous to me. Let's say there is one member who speaks English and Korean.

If that member is considered one of the 60 who 'speak only English', then the above answer C is correct.

But if not, because that member speaks English AND some other language, not 'ONLY English', then guys like him are not mentioned in this question. Then I think the answer would be E.

Don't know if I over-complicated or misunderstood the question.
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by navalpike » Thu Sep 03, 2009 7:19 pm
If the OA is indeed C, can someone find the flaw is my reasoning below.

T = G + E + S-(two of the three) + Neither
200 = G + E + 70-x+ Neither (or n)
130 = G + E-x + n

S1. E = 60
130 = G + 60-x +n
70 = G-x + n.....Insuff.

S2. N = 20
130 = G + E-x + 20
110 = G+E-x .....Insuff.

1+2

G-x = 70-n
G-x = 110-E

Using information from S1 and S2, I am only able to go as far as G-x=50. Why is the answer C?
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by qwe12 » Fri Sep 04, 2009 12:58 am
n_niaz can you please post the official answer?
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