ricky wrote:Set A is composed of nine numbers, labeled A1 through A9. Set B is also composed of nine numbers, labeled B1 through B9. Set B is defined as follows: B1 = 1 + A1; B2 = 2 + A2; and so on, including B9 = 9 + A9. How much larger is the sum of set B's mean and range than the sum of set A's mean and range?
(a) 4
(b) 9
(c) 13
(d) 17
(e) Cannot be determined

We can certainly work out by how much the mean of B exceeds the mean of A. We cannot, however, compare the range of B with the range of A, unless we have more information about the sets- the range of B might be larger than the range of A, or it might be smaller. We could have:

A = {0,0,0,...,0} --- range = 0
B = {1, 2, 3, 4, ..., 9} --- range = 8

and the range of B > the range of A.

Or we could have:

A = {9,8,7,6,5,4,3,2,1} --- range = 8
B = {10,10,10,10,...,10} --- range = 0

and the range of B < the range of A.

So the answer should be E.