BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Sets Problem

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 49
Joined: Thu May 19, 2011 9:20 pm
by sampath » Wed Aug 17, 2011 2:36 am
The Mathematics Club in a school held an open house on three afternoons. 115, 75 and 110 students
attended on the first, second and third afternoons respectively. 30 attended only on the first day, 35 on the first and second days. 70 attended the first and the third days and 35 attended on the second and third days. How many attended on all the three days?
(A) 15 (B) 25 (C) 21 (D) 20 (E) 30
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 34
Joined: Mon Nov 15, 2010 12:12 pm
Thanked: 2 times

by rppala90 » Wed Aug 17, 2011 5:34 am
n(F) = n(F only) + n(F&S) + n(F&T) - n(F&S&T)
F --> First day.
S --> Second day.
T --> Third day.

[spoiler]115 = 30 + 35 + 70 - n(F&S&T)
n(F&S&T) = 135 - 115 = 20
Hence (D)[/spoiler]
I think info about n(S&T), n(S) and n(T) are not needed to solve this question.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 102
Joined: Thu Jul 21, 2011 2:22 amFollowed by: 1 member
Location: Lahore, Pakistan
Thanked: 4 times

by chufus » Wed Aug 17, 2011 5:59 am
rppala90 wrote:n(F) = n(F only) + n(F&S) + n(F&T) - n(F&S&T)
F --> First day.
S --> Second day.
T --> Third day.

[spoiler]115 = 30 + 35 + 70 - n(F&S&T)
n(F&S&T) = 135 - 115 = 20
Hence (D)[/spoiler]
I think info about n(S&T), n(S) and n(T) are not needed to solve this question.
Everything seems correct to your approach. Wonder why the other info was mentioned in the question. Doesn't seem like a GMAT question !
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 9
Joined: Thu Aug 04, 2011 12:07 am

by krishna8143 » Wed Aug 17, 2011 11:05 pm
ans is D 20
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 143
Joined: Sat Nov 06, 2010 9:06 pmFollowed by: 1 member
Thanked: 10 times

by edvhou812 » Wed Aug 17, 2011 11:27 pm
chufus wrote:
rppala90 wrote:n(F) = n(F only) + n(F&S) + n(F&T) - n(F&S&T)
F --> First day.
S --> Second day.
T --> Third day.

[spoiler]115 = 30 + 35 + 70 - n(F&S&T)
n(F&S&T) = 135 - 115 = 20
Hence (D)[/spoiler]
I think info about n(S&T), n(S) and n(T) are not needed to solve this question.
Everything seems correct to your approach. Wonder why the other info was mentioned in the question. Doesn't seem like a GMAT question !
This is a GMAT question.
I don't know what to say, really. Three minutes to the biggest battle of our professional lives. You find out life's this game of inches, so is football. Because in either game - life or football - the margin for error is so small. I mean, one half a step too late or too early and you don't quite make it. One half second too slow, too fast and you don't quite catch it. I'll tell you this, in any fight it's the guy whose willing to die whose gonna win that inch. That's football guys, that's all it is. Now, what are you gonna do?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1