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Start the planA. 4
B. 5
C. 6
D. 10
E. 20
The OA is C.
Factors of 20 = 1, 2, 4, 5, 10, 20
Multiples of 20 = 20, 40, 60, 80, . . . . . . . . . .
So, B={1, 2, 4, 5, 10, 20, 40, 60, 80, . . . . . . . . . . . . .}
x/20 = remaider 0.
Let the minimum value of x = 20
Thus x must be divisible by 1, 2, 4, 5, 10, 20
So, x must also be divisible by 6 members of set B. Option C.
Has anyone another strategic approach to solve this PS question? Regards!














