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Set A of 8 positive integers may have the same element and h

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by Max@Math Revolution » Sun Jun 05, 2016 6:34 pm
Set A of 8 positive integers may have the same element and have 38. And set B of 8 positive integers must have different elements and have 38. When m and n are the greatest possible differences between 38 and other elements' sums in set A and set B, respectively, m-n=?
A. 20
B. 21
C. 23
D. 25
E. 26

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by Max@Math Revolution » Tue Jun 07, 2016 5:45 pm
This is maximum-minimum. Hence, 38-(1+1+1+1+1+1+1)=31 and 38-(1+2+3+4+5+6+7)=10. So, 31-10=21. The correct answer is B.
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