96. If a sequence of numbers is given by An = An-1+15, is A32 an odd number?
(1) A1 is an odd integer
(2) A21 is an odd integer
How would you approach this problem?
Explanation:
On observing the sequence, it is clear that it is an arithmetic progression with common difference 15. So terms will be even and odd alternately.
Statement 1 says A1 is odd, and odd +15(odd) is even, so A2 will be even and A3 odd and so on. So A32 will be even; SUFFICIENT.
Similarly, from statement 2, it is clear that A21, A23, A25 and so on will be odd while A22, A24 and so on will be even. Hence, A32 will be even; SUFFICIENT.
The correct answer is D;
each statement alone is sufficient.
(1) A1 is an odd integer
(2) A21 is an odd integer
How would you approach this problem?
Explanation:
On observing the sequence, it is clear that it is an arithmetic progression with common difference 15. So terms will be even and odd alternately.
Statement 1 says A1 is odd, and odd +15(odd) is even, so A2 will be even and A3 odd and so on. So A32 will be even; SUFFICIENT.
Similarly, from statement 2, it is clear that A21, A23, A25 and so on will be odd while A22, A24 and so on will be even. Hence, A32 will be even; SUFFICIENT.
The correct answer is D;
each statement alone is sufficient.
