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Thank you for emphasizing this! I understand this problem better now. You are correctcramya wrote:
Both k's in the denominator of left hand side and right hand side cancel
C
Hope this helps!
Regards,
CR
BlindVision wrote:if k NOT EQUAL 0 and k - (3 - 2k^2 / k) = x/k, then x =
A) -3 - k^2
B) k^2 - 3
C) 3k^2 - 3
D) k - 3 - 2k^2
E) k - 3 + 2k^2
OA = C
That was how the question was wrote. Could you please show me what you meant, instead of showing an emoticon with rolling eyes? :roll:hrishikesh05 wrote:BlindVision wrote:if k NOT EQUAL 0 and k - (3 - 2k^2 / k) = x/k, then x =
A) -3 - k^2
B) k^2 - 3
C) 3k^2 - 3
D) k - 3 - 2k^2
E) k - 3 + 2k^2
OA = C
Please put the brackets in the correct place. :roll:
it has to be k - [3 - 2k^2]/kif k NOT EQUAL 0 and k - (3 - 2k^2 / k) = x/k, then x =
Plug in k=2 into k - (3 - 2k^2)/k = x/k and solve for x:BlindVision wrote:if k NOT EQUAL 0 and k - (3 - 2k^2)/k = x/k, then x =
A) -3 - k^2
B) k^2 - 3
C) 3k^2 - 3
D) k - 3 - 2k^2
E) k - 3 + 2k^2
OA = C
