BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Sandbox

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 510
Joined: Thu Aug 07, 2014 2:24 amFollowed by: 5 members
Thanked: 3 times
by j_shreyans » Thu Aug 21, 2014 2:33 am
Guys ,

Pls help me out with the below problem..

If a sandbox in the shape of a right triangle has a hypotenuse of h feet, an area of a square feet, and one leg of length x feet, which of the following must be true?

1) x^2-4a^2/x^2-h^2=0
2) x^2+4a^2/x^2+h^2=0
3) x^2+4a^2/x^2-h^2=0
4) x^2+2a^2/x^2-h^2=0
5) x^2+2a^2/x^2+h^2=0

OA3

Thanks

Shreyans
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 1100
Joined: Sat May 10, 2014 11:34 pmFollowed by: 24 members
Location: New Delhi, India
Thanked: 205 times

by GMATinsight » Thu Aug 21, 2014 7:34 am
j_shreyans wrote:Guys ,

Pls help me out with the below problem..

If a sandbox in the shape of a right triangle has a hypotenuse of h feet, an area of a square feet, and one leg of length x feet, which of the following must be true?

1) x^2-4a^2/x^2-h^2=0
2) x^2+4a^2/x^2+h^2=0
3) x^2+4a^2/x^2-h^2=0
4) x^2+2a^2/x^2-h^2=0
5) x^2+2a^2/x^2+h^2=0

OA3

Thanks

Shreyans
Answer: Option C i.e. x^2+(4a^2/x^2)-h^2=0
Attachments
Solution 54.jpg
"GMATinsight"Bhoopendra Singh & Sushma Jha
Most Comprehensive and Affordable Video Course 2000+ CONCEPT Videos and Video Solutions
Whatsapp/Mobile: +91-9999687183 l [email protected]
Contact for One-on-One FREE ONLINE DEMO Class Call/e-mail
Most Efficient and affordable One-On-One Private tutoring fee - US$40-50 per hour
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pmFollowed by: 511 members
Location: Palo Alto, CA
Thanked: 2867 times
GMAT Score:800

by [email protected] » Thu Aug 21, 2014 8:54 am
Hi j_shreyans,

This question is perfect for TESTing Values:

We're dealing with a RIGHT TRIANGLE and we're given the variables...

H = hypoteneuse
X = one of the legs
A = area of the triangle

Let's choose a 3/4/5 right triangle...

H = 5
X = 3
A = (1/2)(3)(4) = 6

Now we just have to test those values in the answers and find the one that's true...

A) 9 - 144/9 - 25 = something negative (not 0)
B) 9 + 144/9 + 25 = something positive (not 0)
C) 9 + 144/9 - 25 = 0
D) 9 + 72/9 - 25 = -8
E) 9 + 72/9 + 25 = something positive (not 0)

Final Answer: C

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
GMAT Instructor
Posts: 2630
Joined: Wed Sep 12, 2012 3:32 pmFollowed by: 119 members
Location: East Bay all the way
Thanked: 625 times
GMAT Score:780

by Matt@VeritasPrep » Thu Aug 21, 2014 2:46 pm
Algebraically ...

Let's call the two legs b and x.

We know that

b² + x² = h²,
(b*x)/2 = a

Since all of the answers are equal to 0 and do NOT include the variable b, we'll try to combine these so b goes away and the whole thing equals 0.

From the first equation,
b² + x² - h² = 0

From the second,
b = (2a)/x

Substituting (2a)/x for b in the first equation ...

((2a)/x)² + x² - h² = 0
4a²/x² + x² - h² = 0

So C.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1