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Sabina took first dip

Expert replies
by sanju09 » Fri Jul 25, 2014 10:11 pm
An enchanted pool is such that if someone takes a dip into it with n flowers in hands, it becomes 2n flowers. Sabina took first dip into the pool with x flowers in her hands and given away y of the resulting number of flowers to Shivangi. She then took a second dip into the pool with the remaining flowers in her hands and again given away y of the resulting number of flowers to Nandini. She ultimately took a third dip into the pool with the remaining flowers in her hands and once again she given away y number of flowers to Rashika with no flower left in her hands. Which of the following is a possible value of x + y?
A. 12
B. 15
C. 18
D. 21
E. 24


Made Up!
The mind is everything. What you think you become. –Lord Buddha



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The Princeton Review - Manya Abroad
Lucknow-226001

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Source: — Problem Solving |

by GMATinsight » Sat Jul 26, 2014 7:43 am
sanju09 wrote:An enchanted pool is such that if someone takes a dip into it with n flowers in hands, it becomes 2n flowers. Sabina took first dip into the pool with x flowers in her hands and given away y of the resulting number of flowers to Shivangi. She then took a second dip into the pool with the remaining flowers in her hands and again given away y of the resulting number of flowers to Nandini. She ultimately took a third dip into the pool with the remaining flowers in her hands and once again she given away y number of flowers to Rashika with no flower left in her hands. Which of the following is a possible value of x + y?
A. 12
B. 15
C. 18
D. 21
E. 24


Made Up!

After First Dip in Pool:
Initial No. of Flowers in Hand = x, Flowers after Dip = 2x, Remaining after giving y flowers = 2x-y

After Second Dip in Pool:
Initial No. of Flowers in Hand = 2x-y, Flowers after Dip = 4x-2y, Remaining after giving y flowers = 4x-3y

After Third Dip in Pool:
Initial No. of Flowers in Hand = 4x-3y, Flowers after Dip = 8x-6y, Remaining after giving y flowers = 8x-7y

[Here is a trend of getting (2^a)x - (2^a-1)y flowers after ath Dip]

After Third Dip No. of Flowers = 0 = 8x-7y

i.e. 8x = 7y
i.e. x=7 and y=8 is the first Integer Solution

x+y = 15 is one of the solutions

Answer: Option [spoiler]B[/spoiler]
Last edited by GMATinsight on Sat Jul 26, 2014 9:44 pm, edited 1 time in total.
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by sanju09 » Sat Jul 26, 2014 9:26 pm
GMATinsight wrote:
sanju09 wrote:An enchanted pool is such that if someone takes a dip into it with n flowers in hands, it becomes 2n flowers. Sabina took first dip into the pool with x flowers in her hands and given away y of the resulting number of flowers to Shivangi. She then took a second dip into the pool with the remaining flowers in her hands and again given away y of the resulting number of flowers to Nandini. She ultimately took a third dip into the pool with the remaining flowers in her hands and once again she given away y number of flowers to Rashika with no flower left in her hands. Which of the following is a possible value of n WHY? + y?
A. 12
B. 15
C. 18
D. 21
E. 24


Made Up!
x+y in question should be read as n+y

After First Dip in Pool:
Initial No. of Flowers in Hand = n, Flowers after Dip = 2n, Remaining after giving y flowers = 2n-y

After Second Dip in Pool:
Initial No. of Flowers in Hand = 2n-y, Flowers after Dip = 4n-2y, Remaining after giving y flowers = 4n-3y

After Third Dip in Pool:
Initial No. of Flowers in Hand = 4n-3y, Flowers after Dip = 8n-6y, Remaining after giving y flowers = 8n-7y

[Here is a trend o getting (2^x)n - (2^x-1)y flowers after xth Dip]

After Third Dip No. of Flowers = 0 = 8n-7y

i.e. 8n=7y
i.e. n=7 and y=8 is the first Integer Solution

n+y = 15 is one of the solutions

Answer: Option [spoiler]B[/spoiler]
I didn't get why x + y be read as n + y here, while the question specifically mentions that Sabina started with x flowers in hands, not n. Although n is mentioned in the beginning just to introduce the nature of pool.
The mind is everything. What you think you become. –Lord Buddha



Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com
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by GMATinsight » Sat Jul 26, 2014 9:41 pm
That was a silly reading mistake !!!

However, it doesn't change the answer. :)
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by theCodeToGMAT » Mon Jul 28, 2014 8:51 pm
n --> 2n --> 4n --> 8n ....

To find (x+y)

x --> 2x (Left=2x-y, shi=y) --> 4x-2y(Left 4x-3y, nan=y)---> 8x-6y(Left=8x-7y, Rashi=y)

8x-7y = 0
8x = 7y
if x=7 & y=8.. then this equation is possible.
So, 7+8 = 15
{B}
R A H U L
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