Running at their respective constant rates, Machine x takes 2 days longer to produce w widgets than Machine Y. At these rates, if the two machines together produce 5w/4 widgets in 3 days, how many days would it take machine X alone to produce 2w widgets?
A)4
B)6
C)8
D)10
E)12
I tried to use a different method rather than the one listed on Quan. Review to solve the problem, but somehow I couldn't.
Rather than let x = days need to finish w widgets, here is what I come up with so far:
Let X = X widgets/day,
Y = Y widgets/day
1): w/X = (w/Y) + 2
2): 5w/4 = (X + Y)*3
From 1), we have 3): Y = wX/(w - 2X)
I plugged 3) into 2), but I came out with something really ugly and got stuck.
Is there anyone able to solve these two equations, or is there anything wrong with these two equation? Thank you.
A)4
B)6
C)8
D)10
E)12
I tried to use a different method rather than the one listed on Quan. Review to solve the problem, but somehow I couldn't.
Rather than let x = days need to finish w widgets, here is what I come up with so far:
Let X = X widgets/day,
Y = Y widgets/day
1): w/X = (w/Y) + 2
2): 5w/4 = (X + Y)*3
From 1), we have 3): Y = wX/(w - 2X)
I plugged 3) into 2), but I came out with something really ugly and got stuck.
Is there anyone able to solve these two equations, or is there anything wrong with these two equation? Thank you.
Last edited by yyz5028 on Tue Aug 17, 2010 4:35 am, edited 3 times in total.
