Runners $X$ and $Y$ started an $18$-mile race at the same time. Runner $X$ completed the course in $6$ hours,

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VJesus12: Legendary Member; Posts: 2276; Joined: Sat Oct 14, 2017 6:10 amFollowed by: 3 members

by VJesus12 » Thu Jul 30, 2020 9:17 am

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Runners $X$ and $Y$ started an $18$-mile race at the same time. Runner $X$ completed the course in $6$ hours, and Runner $Y$ finished $2$ hours earlier. Runner $Y$ ran an average of how many miles per hour faster than Runner $X?$

A. $1$

B. $1\frac12$

C. $2\frac14$

D. $3$

E. $4\frac12$

[spoiler]OA=B[/spoiler]

Source: Princeton Review

Source: Beat The GMAT — Problem Solving | Thu Jul 30, 2020 9:17 am

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Re: Runners $X$ and $Y$ started an $18$-mile race at the same time. Runner $X$ completed the course in $6$ hou

by Scott@TargetTestPrep » Wed Aug 05, 2020 9:59 am

VJesus12 wrote: ↑
Thu Jul 30, 2020 9:17 am
Runners $X$ and $Y$ started an $18$-mile race at the same time. Runner $X$ completed the course in $6$ hours, and Runner $Y$ finished $2$ hours earlier. Runner $Y$ ran an average of how many miles per hour faster than Runner $X?$

A. $1$

B. $1\frac12$

C. $2\frac14$

D. $3$

E. $4\frac12$

[spoiler]OA=B[/spoiler]

Solution:

The average speed of runner X is 18/6 = 3 mph, and the average speed of runner Y is 18/4 = 4.5 mph. Therefore, the average speed of runner Y is 4.5 - 3 = 1.5 mph faster than the average speed of runner X.

Answer: B

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