Plug in the values !!

A) u get 0 which is a real number
B)root2 is 1.41 ... so 2-1.41 is 0.61
root of 0.61 is < 1
so when 1 is subtracted ! it is again some numebr which is a real number

C) root 3 is 1.73 !! so u go in the same line as B) and u get a real number
D)u get 0 as the answer
E)root 5 is >2 .. so 2- root 5 is negative which is not real number

OA E

VIshu

for results to be imaginary

x can be -ve
but not given so move one step out

2 - sqrt(x) has to be < 1

so if sqrt(x) is > 2 we are done
which is possible with x=5

so we have solved it at 1 level.
in some cases we may be required to move out....

For X to be not real, sqrt x > 2 ( Based on the equation)

Square it ob both sides

x >4

Only one option E

Dont do intensive calculations !