Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 563 reviewsTarget Test Prep

Rooted!

Expert replies
Post new topic Post Reply
Subscribe topic
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 167
Joined: Wed Jun 11, 2008 10:58 pmFollowed by: 1 member
Thanked: 2 times
by zagcollins » Mon Jul 21, 2008 6:46 am
Stuck after a certain pt..I need to devise new ways to tackle problems and not get bogged down...grrrrr :evil:
You do not have the required permissions to view the files attached to this post.
Top
Join the discussion
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 27
Joined: Thu Mar 20, 2008 8:00 am
Location: France

by louvre » Mon Jul 21, 2008 7:21 am
I think it's 4!
Oh My...took really long to solve.
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 167
Joined: Wed Jun 11, 2008 10:58 pmFollowed by: 1 member
Thanked: 2 times

by zagcollins » Mon Jul 21, 2008 7:31 am
the answer is 4..can you please post a detailed explanation of the same?
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 198
Joined: Fri Mar 09, 2007 8:40 pm
Thanked: 7 times

by kris610 » Mon Jul 21, 2008 7:53 am
zagcollins wrote:the answer is 4..can you please post a detailed explanation of the same?
First take the right side of the given equation: (2/(8+sqrt(63)). Multiply both the numerator and denominator by (8-sqrt(63)) and then add the left side in the equation (2+sqrt(63)). You will see that this term cancels out and you will be left with sqrt(16).

It will be pretty easy when you actually solve this on paper.
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 167
Joined: Wed Jun 11, 2008 10:58 pmFollowed by: 1 member
Thanked: 2 times

by zagcollins » Mon Jul 21, 2008 8:03 am
still don't get it...grrrrr...
Top
Join the discussion
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

by sudhir3127 » Mon Jul 21, 2008 8:04 am
Sq root ( 2rsqt63 + 2/(8+3sqrt7) )

sq rt ( 2* sqrt (9*7) + 2/(8+3sqrt7) )... ( 63 can be written as 9*7)

sq rt ( 6 sqrt7 + 2 / (8+3sqrt7) )

lcm is 8+3sqrt7

sq root ( 48 sqrt 7 + 126 + 2 ) /(8+3sqrt7)

sqroot ( 16 ( 3 sqrt7 + 8 ) / (8+3sqrt7))

which is equal to sqroot (16)

hence 4.

hope this is clear.
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 167
Joined: Wed Jun 11, 2008 10:58 pmFollowed by: 1 member
Thanked: 2 times

by zagcollins » Mon Jul 21, 2008 9:38 am
thanks sudhir...now its clearer..solved it myself this time...
Top
Join the discussion