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Rodrick mixes a martini that has a volume of 'n' ounces havi

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by rakeshd347 » Sun Oct 06, 2013 6:29 pm
Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?

A) n/6
B) n/3
C) 3n/5
D) 5n/6
E) 8n/5

OA is C

Can someone please explain me this. I always have issues with mixture problems. What do you think is the difficulty level of this question.
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Source: — Problem Solving |

by GMATGuruNY » Sun Oct 06, 2013 7:11 pm
rakeshd347 wrote:Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?

A) n/6
B) n/3
C) 3n/5
D) 5n/6
E) 8n/5

OA is C
Let V = vermouth and G = gin.

Original solution:
V:G = 40:60 = 2:3.
Let V = 2 ounces and G = 3 ounces.
Thus, n = 2+3 = 5 ounces.

New solution:
After more gin is added, the amount of vermouth -- 2 ounces -- must be 1/4 of the new volume.
Since 2 is 1/4 of 8, the new volume must be 8 ounces.
Thus, the amount of added gin = new volume - old volume = 8-5 = 3 ounces. This is our target.

Now plug n=5 into the answers to see which yields our target of 3.
Only C works:
3n/5 = (3*5)/5 = 3.

The correct answer is C.
Last edited by GMATGuruNY on Mon Oct 07, 2013 5:15 am, edited 1 time in total.
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by rakeshd347 » Sun Oct 06, 2013 7:31 pm
GMATGuruNY wrote:
rakeshd347 wrote:Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?

A) n/6
B) n/3
C) 3n/5
D) 5n/6
E) 8n/5

OA is C
Let V = vermouth and G = gin.

Original solution:
V:G = 40:60 = 2:3.
Let V = 2 ounces and G = 3 ounces.
Thus, n = 2+3 = 5 ounces.

New solution:
After more gin is added, the amount of vermouth -- 2 ounces -- must be 1/4 of the new volume.
Since 2 is 1/4 of 8, the new volume must be 8 ounces.
Thus, the amount of added gin = new volume - old volume = 8-5 = 3 ounces. This is our target.

Now plug n=5 into the answer to see which yields our target of 3.
Only C works:
3n/5 = (3*5)/5 = 3.

The correct answer is C.
Mitch when you solved a question it looks like 500 level difficulty when I solved it, then it looks like 700 difficulty.
You must have done some PHD and R& D in gmat question mate.

Thanks for that mate my headache is gone now :)
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by Brent@GMATPrepNow » Sun Oct 06, 2013 9:09 pm
rakeshd347 wrote:Rodrick mixes a martini that has a volume of 'n' ounces having 40% Vermouth and 60% Gin by volume. He wants to change it so that the martini is 25% Vermouth by volume. How many ounces of Gin must he add?

A) n/6
B) n/3
C) 3n/5
D) 5n/6
E) 8n/5
For mixture questions, I find it helpful to draw the mixtures with their components separated.
This will allow you to visualize the question, and it makes it easy to add individual components.
Image
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
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by theCodeToGMAT » Sun Oct 06, 2013 9:22 pm
Let n = 100
Vermouth = 40
Gin = 60

Gin is added 60+x to make percentage 75%
60+x/100+x = 3/4
x = 60

3n/5 = 60
Answer [spoiler]{C}[/spoiler]
R A H U L
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