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Right cylinder

Problem Solving — algebra and arithmetic
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Newbie | Next Rank: 10 Posts
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Location: Tustin
by JinalShah » Tue Jun 17, 2008 1:39 pm
Hi,
I was going through Manhattan GMAT geometry book - chapter 3, question 10 regarding rectangular box with the dimensions of 12 inch, 10 inch, 8 inch and is asked to find largest possible volume of right cylinder that is placed inside the box....

I referred to the answer explanation where in only three possibilities are considered... case 1: r=5 & h=8 ; case 2 : r=4 & h=10 ; case 3 : r=4 & h=12... why other possibilities are not considered such as case 4 : r=6 & h=10 ; case 5 : r=6 & h=8 ; case 6 r=5 & h=12.... If case 4,5 and 6 is considered answer changes to 360 TT
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Source: — Quantitative Reasoning |
Junior | Next Rank: 30 Posts
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Re: Right cylinder

by altin » Wed Jun 18, 2008 4:00 pm
Because you cannot put cylinder r=6 into that box if r=6 diameter is 12
means box should be at least 12x12
Case 6 is similar if r=5 you have to use 12x10 side for cylinder base and height cannot be more than 8
JinalShah wrote:Hi,
I was going through Manhattan GMAT geometry book - chapter 3, question 10 regarding rectangular box with the dimensions of 12 inch, 10 inch, 8 inch and is asked to find largest possible volume of right cylinder that is placed inside the box....

I referred to the answer explanation where in only three possibilities are considered... case 1: r=5 & h=8 ; case 2 : r=4 & h=10 ; case 3 : r=4 & h=12... why other possibilities are not considered such as case 4 : r=6 & h=10 ; case 5 : r=6 & h=8 ; case 6 r=5 & h=12.... If case 4,5 and 6 is considered answer changes to 360 TT
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