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Rhombus

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by crackgmat007 » Fri Oct 02, 2009 7:26 pm
Is quadrilateral ABCD a rhombus?

1. AC is perpendicular to BD
2. AB + CD = BC + AD

OA - E

Can someone explain?
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Source: — Data Sufficiency |
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by srivas » Fri Oct 02, 2009 9:39 pm
Propeties of Rhombus

1. daigonal bisect perpendicular
2. All sides are congurent(eqqual in lenght)

From Statement I
we know about daigonal but no information on sides
From Statement II
we cannot say sides are equal
Gmat710,, Hyd
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by crackgmat007 » Sat Oct 03, 2009 9:43 am
A square is a rhombus. From 1, since diagonals bisect, can we not say that the quadrilatoral is a square?
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by m&m » Sat Oct 03, 2009 10:05 am
crackgmat007 wrote:A square is a rhombus. From 1, since diagonals bisect, can we not say that the quadrilatoral is a square?
...not necessarily, the diagonals can bisect to form a 90-degree angle without necessarily having a square. To prove to yourself draw 2 lines that intersect at 90-deg and make one of the lines much longer than the other, then connect all the ends to form quadrilateral... this is not necessarily a square.
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