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Rhombus

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by csandeepreddy » Sat Oct 18, 2008 10:32 am
Is quadrilateral ABCD a rhombus?

(1) Line segments AC and BD are perpendicular bisectors of each other.

(2) AB = BC = CD = AD
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Re: Rhombus

by Morgoth » Sat Oct 18, 2008 11:40 am
csandeepreddy wrote:Is quadrilateral ABCD a rhombus?

(1) Line segments AC and BD are perpendicular bisectors of each other.

(2) AB = BC = CD = AD
Statement (1)

Ac and BD are bisect each other at 90 degree, this is property of both square and a rohmbus. Insufficient.

Statement (2)

AB = BC = CD = AD

Same as above, could be a rohmbus or a square. Insufficient.

Combining (1) & (2)

Still it could a rohmbus or a square. Insufficient


Hence E. OA?
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by csandeepreddy » Sat Oct 18, 2008 1:14 pm
The OA is D
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by Morgoth » Sat Oct 18, 2008 1:29 pm
csandeepreddy wrote:The OA is D
I apologize for the silly mistake,

All squares are rohmbus, but not all rohmbus are squares.

Therefore, each statement should be sufficient.
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by appmentor-jon » Sat Oct 18, 2008 8:00 pm
For anyone who (like me) didn't remember what a rhombus is:
Rhombus - A parallelogram with four congruent sides
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by kris610 » Sat Oct 25, 2008 1:33 pm
How is A sufficient?

A quadrilateral with diagonals that bisect each other at right angles could be a kite.

A kite with 4 equal sides is a rhombus.

B by itself is sufficient.
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