BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Resignations problem

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 123
Joined: Mon Feb 07, 2011 12:11 pmFollowed by: 1 member
by rupsk » Sat Jul 09, 2011 7:26 am
Currently, y percent of the members on the finance committee are women and next month, z percent of the men on the finance committee will resign. If no other personnel changes occur, then after the resignations next month, the men who remain on the finance committee will represent what percent of the total finance committee members?


(100)(100 - z)(100 - y)
_____________________
1002 - z(100 - y)


(100 - z)(100 - y)
_______________
100

(100 - z)(100 - y)


zy
________
100 - z


z(100 - y)
_________
100


I had applied below logic
Committee member = T
women member = Ty/100
men member = T-(Ty/100)
men remained after resignation= (1-(z/100))(100-y/100)T
so percentage is = ((100-z)/100)(100-y/100)*100
=(100-z)(100-y)/100

but this is not correct answer. Please tell me where I got wrong?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 1448
Joined: Tue May 17, 2011 9:55 amFollowed by: 53 members
Location: India
Thanked: 375 times

by Frankenstein » Sat Jul 09, 2011 8:15 am
rupsk wrote: I had applied below logic
Committee member = T
women member = Ty/100
men member = T-(Ty/100)
men remained after resignation= (1-(z/100))(100-y/100)T
so percentage is = ((100-z)/100)(100-y/100)*100
=(100-z)(100-y)/100

but this is not correct answer. Please tell me where I got wrong?
Hi,
Denominator will not be T, As z% resigned, the total number of members remaining will be T - T(1-y/100)(z/100).
So percentage is 100*(1-(z/100))(100-y/100)T/T[1-(1-y/100)(z/100)]

Hence, A
Cheers!

Things are not what they appear to be... nor are they otherwise
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 123
Joined: Mon Feb 07, 2011 12:11 pmFollowed by: 1 member

by rupsk » Sat Jul 09, 2011 8:26 am
Thanks a lot.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Mon Jul 11, 2011 8:28 am
rupsk wrote:Currently, y percent of the members on the finance committee are women and next month, z percent of the men on the finance committee will resign. If no other personnel changes occur, then after the resignations next month, the men who remain on the finance committee will represent what percent of the total finance committee members?


A.(100)(100 - z)(100 - y) / 100^2 - z(100 - y)


B.(100 - z)(100 - y) / 100

C.(100 - z)(100 - y)

D.zy / 100 - z

E.z(100 - y) / 100


I had applied below logic
Committee member = T
women member = Ty/100
men member = T-(Ty/100)
men remained after resignation= (1-(z/100))(100-y/100)T
so percentage is = ((100-z)/100)(100-y/100)*100
=(100-z)(100-y)/100

but this is not correct answer. Please tell me where I got wrong?
Much easier to plug in numbers.

Let total = 100.
Let y = 50.
Since y=50% of the 100 members are women, women = 50, men = 50.
Let z = 50.
Thus, men who resign = .5*50 = 25.
Remaining men = 50-25 = 25.
Total members left = 100-25 = 75.
Men/Total = 25/75 = 33.33%. This is our target.

Now we plug y=50 and z=50 into the answers to see which yields our target of 33.33.

Only answer choice A works:
(100)(100 - z)(100 - y) / 100^2 - z(100 - y)
= 100(100-50)(100-50) / (100)(100) - 50(100-50)
= 100*50*50 / 100*100 - 50*50
= 100*50*50 / 50*50 (2*2 - 1)
= 100/3 = 33.33.

The correct answer is A.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1