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by Mo2men » Mon Sep 12, 2016 4:09 am
If a certain number X is divided by 82, the reminder is 5. what is the reminder when X+11 is divided by 41?

A. 3
B. 5
C. 6
D. 16
E. 18

[spoiler]OA:D[/spoiler]
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by DavidG@VeritasPrep » Mon Sep 12, 2016 5:36 am
Mo2men wrote:If a certain number X is divided by 82, the reminder is 5. what is the reminder when X+11 is divided by 41?

A. 3
B. 5
C. 6
D. 16
E. 18

[spoiler]OA:D[/spoiler]
The easiest scenario x = 5. x + 11 = 16. 16 divided by 82 would give a remainder of 16. And we're done. D is the answer. (Anytime the denominator is greater than the numerator, the remainder is simply the numerator.)
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by 0ld » Mon Sep 12, 2016 7:06 am
X may be (82+5 = 87 ) , (82 * 2 +5 = 87 ) = 169 , 251.

We will take min possible value of X=87.

(x+11)/41 ==> (87+11)/41 = 98/41 = 2 16/41 ==> (Ans D.16)
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by Matt@VeritasPrep » Thu Sep 15, 2016 7:31 pm
Let's pick x = 82 + 5, or x = 87.

From there (87 + 11) / 41 => 98/41 => 2, with remainder 16
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