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by maihuna » Sat May 02, 2009 12:37 pm
What least no must be subtracted from each of the nos 14, 17, 34 and 42 so that the remainder may be proportional:

0
1
2
7
9
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by dumb.doofus » Sat May 02, 2009 12:49 pm
I just didnt get this question.. bouncer.. someone please explain..

even after subtracting.. what are we looking for:

a) 14, 17, 34, 42
b) 13, 16, 33, 41
c) 12, 15, 32, 40
d) 7, 10, 27, 35
e) 5, 8, 25, 33

Now what??
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by maihuna » Sun May 03, 2009 9:25 am
hey dumb here we go:

14-x, 17-x, 34-x and 42-x to be proportional

14-x 34-x
----- = -------
17-x 42-x

=>(14-x)(42-x) = (34-x)(17-x)
=>14*42 -56x +x^2 = 34*17 -51x + x^2
=>14*42-34*17 = 5x
=>2(294-289) => 10= 5x or x=2

so 12 15 32 and 40 will be proportional
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by dumb.doofus » Sun May 03, 2009 9:33 am
maihuna wrote:hey dumb here we go:

14-x, 17-x, 34-x and 42-x to be proportional

14-x 34-x
----- = -------
17-x 42-x

=>(14-x)(42-x) = (34-x)(17-x)
=>14*42 -56x +x^2 = 34*17 -51x + x^2
=>14*42-34*17 = 5x
=>2(294-289) => 10= 5x or x=2

so 12 15 32 and 40 will be proportional
That was pretty simple stuff man.. I just didnt get the question.. question, in my opinion, is not worded correctly..

anyways, thanks buddy..
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