BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

remainder

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 588
Joined: Sun Oct 16, 2011 9:42 amFollowed by: 9 members
Location: New Delhi, India
Thanked: 130 times
GMAT Score:720

by rijul007 » Sat Jan 14, 2012 9:40 am
are you sure the ques is correct??

I am getting 2 as the ans...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 626
Joined: Fri Dec 23, 2011 2:50 amFollowed by: 10 members
Location: Ahmedabad
Thanked: 31 times

by ronnie1985 » Sat Jan 14, 2012 10:44 am
Please read the question carefully. It asks what is the remainder when 7 is divided by 10^something, which is greater than 7 and hence remainder will be 7 only (D). If the question had been what's the remainder when 10^548 is divide by 7 then
Consider R(x/y) = z means remainder when x is divided by y is equal to z
R(10^548/7)=R(3^548/7)=R(9^274/7)=R(8^91x2/7)=R(1x2/7)=R(2/7)=2
Hence 2 is the remainder in that case which is not given in the options.
Follow your passion, Success as perceived by others shall follow you
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 382
Joined: Thu Mar 31, 2011 5:47 pm
Thanked: 15 times

by ArunangsuSahu » Sat Jan 14, 2012 11:09 am
(D)

if 10^548/7 then 2
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 88
Joined: Sat Oct 15, 2011 6:38 pmFollowed by: 1 member
Thanked: 1 times

by gmatpup » Tue Jan 17, 2012 9:00 am
Normally when I am faced with a remainder question I break the larger number down into its primes.. In this case it would be 137 (because I break down the 548) so I am getting a remainder of 0.05
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 57
Joined: Mon Dec 21, 2009 6:27 am
Location: Melbourne, Australia
Thanked: 17 times

by [email protected] » Tue Jan 17, 2012 5:53 pm
ronnie1985 wrote:Please read the question carefully. It asks what is the remainder when 7 is divided by 10^something, which is greater than 7 and hence remainder will be 7 only (D). If the question had been what's the remainder when 10^548 is divide by 7 then
Consider R(x/y) = z means remainder when x is divided by y is equal to z
R(10^548/7)=R(3^548/7)=R(9^274/7)=R(8^91x2/7)=R(1x2/7)=R(2/7)=2
Hence 2 is the remainder in that case which is not given in the options.


Could you please explain how you have derived R(9^274/7)=R(8^91x2/7)=R(1x2/7)?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 626
Joined: Fri Dec 23, 2011 2:50 amFollowed by: 10 members
Location: Ahmedabad
Thanked: 31 times

by ronnie1985 » Wed Jan 18, 2012 12:17 am
[email protected] wrote:
ronnie1985 wrote:Please read the question carefully. It asks what is the remainder when 7 is divided by 10^something, which is greater than 7 and hence remainder will be 7 only (D). If the question had been what's the remainder when 10^548 is divide by 7 then
Consider R(x/y) = z means remainder when x is divided by y is equal to z
R(10^548/7)=R(3^548/7)=R(9^274/7)=R(8^91x2/7)=R(1x2/7)=R(2/7)=2
Hence 2 is the remainder in that case which is not given in the options.


Could you please explain how you have derived R(9^274/7)=R(8^91x2/7)=R(1x2/7)?


3^548 = (3^2*274) = 9^274
Follow your passion, Success as perceived by others shall follow you
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 626
Joined: Fri Dec 23, 2011 2:50 amFollowed by: 10 members
Location: Ahmedabad
Thanked: 31 times

by ronnie1985 » Wed Jan 18, 2012 12:24 am
ronnie1985 wrote:
[email protected] wrote:
ronnie1985 wrote:Please read the question carefully. It asks what is the remainder when 7 is divided by 10^something, which is greater than 7 and hence remainder will be 7 only (D). If the question had been what's the remainder when 10^548 is divide by 7 then
Consider R(x/y) = z means remainder when x is divided by y is equal to z
R(10^548/7)=R(3^548/7)=R(9^274/7)=R(8^91x2/7)=R(1x2/7)=R(2/7)=2
Hence 2 is the remainder in that case which is not given in the options.


Could you please explain how you have derived R(9^274/7)=R(8^91x2/7)=R(1x2/7)?


3^548 = (3^2*274) = 9^274


Also when 9 is divided by 7 remainder is 2
so R(9^274/7) = R(2^274/7)
Please note that 2^273 = 2^3*91=8^91
2^274 = (8^91)*2
therefore, R(2^274/7) = R(((8^91)*2)/7)
Also note 8 divided by 7 leaves 1 as remainder.
Therefore remainder R(((8^91)*2)/7) = R(1*2/7) = 2

I hope now it is easy to undersdtand
Follow your passion, Success as perceived by others shall follow you
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 57
Joined: Mon Dec 21, 2009 6:27 am
Location: Melbourne, Australia
Thanked: 17 times

by [email protected] » Wed Jan 18, 2012 1:44 am
Initially I didn't understand the part "Also when 9 is divided by 7 remainder is 2 so R(9^274/7) = R(2^274/7) "
Thanks mate!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 17
Joined: Fri Jan 20, 2012 8:49 pm

by abby17 » Fri Jan 20, 2012 10:19 pm
I assume the question is 10^548/7

Since 7 and 10 are co-prime, divide the given power (548) by 6(one less than the divisor). This division gives 2 as the remainder.
So the question now reduces to what is the remainder when 10^2 is divided by 7.
Now this is very easy to solve. 100/7 gives 2 as the remainder.

Hope this helps.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1