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Hi Rich,[email protected] wrote:Hi Uva@90,
I'm going to give you a couple of hints so that you can attempt this question again:
1) The largest rectangular solid that can be placed in a cylinder will have a SQUARE base.
2) Draw a picture of what you would see if you looked "down" into the cylinder (you'll see a circle with a square in it). The diagonal of the square will equal the diameter of the circle.
GMAT assassins aren't born, they're made,
Rich
It is true that for a fixed perimeter, the rectangle that maximizes the area would be a square. (And remember that all squares are, in fact, rectangles.)Am I correct to say
For a given Area
Square has the maximum Area with minimum Perimeter.
Rectangle has the maximum Perimeter with minimum Area.
Please suggest.
lets say a area of 4 sqcm.
side of square = 2
Perimeter = 4 * 2 = 8
side of rectangle can be = 2 & 2 with Perimeter = 2(2 + 2) = 8
side of rectangle can be = 4 & 1 with Perimeter = 2(4 + 1) = 10
Similarly, if you had two rectangles with equal area, one square and one non-square, the non-square would have the larger perimeter. (Which makes sense. If we took the non-square, kept the perimeter the same, and made it into a square, the area would then increase.)Am I correct to say
For a given Area
Square has the maximum Area with minimum Perimeter.
Rectangle has the maximum Perimeter with minimum Area.
Please suggest.
lets say a area of 4 sqcm.
side of square = 2
Perimeter = 4 * 2 = 8
side of rectangle can be = 2 & 2 with Perimeter = 2(2 + 2) = 8
side of rectangle can be = 4 & 1 with Perimeter = 2(4 + 1) = 10
Nikhil,nikhilgmat31 wrote:Am I correct to say
For a given Area
Square has the maximum Area with minimum Perimeter.
Rectangle has the maximum Perimeter with minimum Area.
Please suggest.
lets say a area of 4 sqcm.
side of square = 2
Perimeter = 4 * 2 = 8
side of rectangle can be = 2 & 2 with Perimeter = 2(2 + 2) = 8
side of rectangle can be = 4 & 1 with Perimeter = 2(4 + 1) = 10
