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by Brent@GMATPrepNow » Sat Jan 10, 2009 3:29 pm
If the length and width of rectangle R were each increased by 1, the area would be 72. If the length and width of rectangle R were each decreased by 1, the area would be 35. What is the perimeter of rectangle R?
(A) 24
(B) 37
(C) 48
(D) 50
(E) 51
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by arzanr » Sat Jan 10, 2009 3:56 pm
B. 37
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by logitech » Sat Jan 10, 2009 4:32 pm
arzanr wrote:B. 37
Great solution Arzanr! :)

(x+1)(y+1)=72
(x-1)(y-1)=35

xy+x+y=71
xy-x-y=34

if we substract 2nd equation from the 1st

2(x+y)= 37, where 2(x+y) is the perimeter
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by Brent@GMATPrepNow » Sat Jan 10, 2009 4:52 pm
Yes, the answer is B - nice work
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