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Rectangle ABCD is inscribed in a circle with center X.

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by AAPL » Tue Oct 02, 2018 2:59 am
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Veritas Prep

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Rectangle ABCD is inscribed in a circle with center X. If the area of the rectangle is eight times its width, and the distance from X to side AB is three, what is the approximate circumference of the circle?

A. 5
B. 10
C. 30
D. 45
E. 75

OA C.
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Source: — Problem Solving |

by mongmat27 » Tue Oct 02, 2018 5:36 am
Ans is C - 30

Let length be a and width be b

Given - ab =8b

Thus, a=8

Thus, AB =8

Distance from centre to AB is 3. Let this line drawn from X (centre of circle) to AB meet AB at E. Thus, XE = 3

As X is the centre, XE will be perpendicular bisector to AB. Thus, EB = 4

Triangle EBX is a right angled triangles with one side =3 and other =4. Thus, the third side XB, which is the radius of the circle (because X is centre and B is a point on the circle) = 5 (Pythagoras theorem)

Thus, circumference = 2*3.14*5 = 31.4

option C is the closest approximation of 31.4
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by Scott@TargetTestPrep » Wed Oct 03, 2018 4:58 pm
AAPL wrote:Veritas Prep

Image

Rectangle ABCD is inscribed in a circle with center X. If the area of the rectangle is eight times its width, and the distance from X to side AB is three, what is the approximate circumference of the circle?

A. 5
B. 10
C. 30
D. 45
E. 75
Since the area of the rectangle is eight times its width, the length of the rectangle (AB or CD) is 8. Since the distance from X to side AB is 3, the distance from X to side CD is also 3. Therefore, AD or BC, that is, the width of the rectangle is 6. By the Pythagorean theorem, we have:

AC^2 = AB^2 + BC^2

AC^2 = 8^2 + 6^2

AC^2 = 100

AC = 10

Since AC is also the diameter of the circle, the circumference of the circle is AC x π, or 10π. Since π is approximately 3, the circumference is approximately 30.

Answer: C

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