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Reciprocals

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by TuanNguyen87 » Thu Jun 09, 2011 12:21 am
In an electric circuit, two resistors with resistances x and y are connected in parallel. In this case, if r is the combined resistance of these two resistors, then the reciprocal of r is equal to the sum of the reciprocals of x and y. What is r in terms of x and y?

A. xy
B. x + y
C. 1/(x+y)
D. xy/(x+y)
E. (x+y)/xy

Answer: D

Thanks a lot in advance!!!
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Source: — Problem Solving |

by Frankenstein » Thu Jun 09, 2011 12:23 am
Hi,
(1/r) = (1/x)+(1/y) = (x+y)/xy
So, r = xy(x+y)

Hence, D
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by cans » Thu Jun 09, 2011 12:25 am
1/r = 1/x + 1/y = (x+y)/xy
thus r = xy/(x+y)
IMO D
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by TuanNguyen87 » Thu Jun 09, 2011 12:26 am
Frankenstein wrote:Hi,
(1/r) = (1/x)+(1/y) = (x+y)/xy
So, r = xy(x+y)

Hence, D
Wow you're so smart and quick :shock: But can you explain for me more about reciprocals? I have no idea about this. Thanks so much!!!!
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by TuanNguyen87 » Thu Jun 09, 2011 12:27 am
You guys are really smart :shock: Thanks!!!
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by kcstej » Thu Jun 09, 2011 12:29 am
1/r= 1/x + 1/y
1/r= (x+y)/xy
r= xy/(x+y)

So D
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by Frankenstein » Thu Jun 09, 2011 1:00 am
TuanNguyen87 wrote:
Frankenstein wrote:Hi,
(1/r) = (1/x)+(1/y) = (x+y)/xy
So, r = xy(x+y)

Hence, D
Wow you're so smart and quick :shock: But can you explain for me more about reciprocals? I have no idea about this. Thanks so much!!!!
Hi,
If you have any specific doubt about reciprocals or whatever, you can just PM me.
Cheers!

Things are not what they appear to be... nor are they otherwise
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by GMATGuruNY » Thu Jun 09, 2011 2:05 am
TuanNguyen87 wrote:In an electric circuit, two resistors with resistances x and y are connected in parallel. In this case, if r is the combined resistance of these two resistors, then the reciprocal of r is equal to the sum of the reciprocals of x and y. What is r in terms of x and y?

A. xy
B. x + y
C. 1/(x+y)
D. xy/(x+y)
E. (x+y)/xy

Answer: D

Thanks a lot in advance!!!
We can plug in values for x and y.

Let x=2, y=3.
Then the reciprocals of x and y are 1/2 and 1/3.
Since the reciprocal of r is equal to the sum of the reciprocals of x and y, we get:
1/r = 1/2 + 1/3
1/r = 3/6 + 2/6
1/r = 5/6
r = 6/5. This is our target.

Now we plug x=2 and y=3 into the answers to see which yields our target of 6/5.

Only answer choice D works:
xy/(x+y) = (2*3)/(2+3) = 6/5.

The correct answer is D.
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by MBA.Aspirant » Thu Jun 09, 2011 5:34 am
TuanNguyen87 wrote:In an electric circuit, two resistors with resistances x and y are connected in parallel. In this case, if r is the combined resistance of these two resistors, then the reciprocal of r is equal to the sum of the reciprocals of x and y. What is r in terms of x and y?

A. xy
B. x + y
C. 1/(x+y)
D. xy/(x+y)
E. (x+y)/xy

Answer: D


Thanks a lot in advance!!!

1/r = 1/x + 1/y

1/r = x+y/xy

r = xy / x+y
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by Buix0065 » Fri Jul 22, 2011 1:54 pm
In this problem it states that r is the combined resistance of x and y.

So why isn't the correct answer X + Y ? Clearly I'm misunderstanding the wording of the question, just wouldn't want to miss something like this on the actual!
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