myselfhari wrote:Find the product of all the factors of 432.
A. (512)^20
B. (216)^20
C. (432)^20
D. (432)^10
E. (216)^20
I need a easy method to solve this tricky one.
Please help
Express 432 as a product of its prime factors.
(3^3)*(2^4)
Increment the powers of each of the prime factors.
(3^4 )* (2^5)
Product of the incremented numbers( powers )
4*5 = 20
The product of all factors of 432 is
432^(number of factors/2)
432^(20/2)
432^10
Hence answer is D...
The tricks for solving such problems is -
1. First find out the prime factors of the number
2. Increase the powers of the factor by 1 and multiply them.
3. Raise the no ^( Increased the powers )/2
Abhishek