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by vaibhav101 » Thu May 31, 2018 8:31 am
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a sum of $1300 is divided among p,q,r and ,s such that $$\frac{p's\ share}{q's\ share}=\frac{q's\ share}{r's\ share}=\frac{r's\ share}{s's\ share}=\frac{2}{3}$$ . Then p's share is
A $140
B $160
C $ 240
D $ 320
E $325
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by Sionainn@PrincetonReview » Thu May 31, 2018 2:30 pm
While you can solve this algebraically using the system of equations (3p = 2q, 3q = 2r, 3r = 2s and p + q + r + s = 1300), because of the time restrictions on the test this one works well for plugging in the answers. Start with the middle choice and assume p = 240. If p = 240, then q = 360, r = 540 ans s = 810. However the total of these values is greater than 1300, so this answer is not correct. Try a smaller number. If p = 160, q = 240, r = 360 and s = 540. In this case p + q + r + s does equal 1300, so this is the answer. The answer is choice B.

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