Ratio

T.A/S>3/80

5/S>3/80

400>3S

400/3>S

133.33>S

133 should be your answer.

you can also cross multiply the ratio's to find out which one will be the maximum value. For example:

Let's take 131 -

5 / 131 > 3 / 80 - now cross multliply

80 * 5 > 131 * 3 - true

I would go with 133 as well, its asking maximum number of students so 130-133 satisfy ratio > 3/80, 133 being maximum while for 134 ratio is less

**typing mistake

must always be greater than 3:80

id go with 134,

Didn't got that?

hongwang9703 wrote:must always be greater than 3:80

id go with 134,

Greater ratio means more teachers , less students. So students cannot exceed 133.33.
So 133 is correct.

hpgmat wrote:At a certain university, the ratio of the number of teaching assistants to the number of students in any Course must always be greater than 3:80. at this university, what is the maximum number of students Possible in a course that has 5 teaching assistants?
130
131
132
133
134

We are given that the ratio of the number of teaching assistants to the number of students in any course must always be greater than 3:80, and we need to determine the maximum number of students possible in a course that has 5 teaching assistants. Let’s use the following formula, in which t = 5 = the number of teaching assistants and s = the number of students.

t/s> 3/80

5/s > 3/80

400 > 3s

400/3 > s

133.33 > s

Since s must be a whole number, the largest possible value of s is 133.

Answer: D