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by raulverde » Mon Jul 30, 2007 10:50 am
Gold is 19 times heavier than water. Copper is 9 times heavier than water. In what ratio should Gold and Copper be mixed to get an alloy 15 times heavier than water.

Source : Quantitative Aptitude by R.S Aggarwal
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by givemeanid » Mon Jul 30, 2007 11:18 am
C*(15-9) = G*(19-15)
6C = 4G
C/G = 4/6 = 2/3
So It Goes
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by sally123 » Mon Jul 30, 2007 11:33 am
givemeanid
Can you please elaborate the solution
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by raulverde » Mon Jul 30, 2007 11:37 am
The answer is right....but please elaborate
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by givemeanid » Mon Jul 30, 2007 11:54 am
(percent/price difference between weaker solution and desired solution) x (amount of weaker solution) = (percent/price difference between the stronger solution and desired solution) x (amount of stronger solution)

Here, weaker alloy is copper (9 times heavier than water)
Desired alloy is 15 times heavier than water
Stronger alloy is gold (19 times heavier than water)

Let quantity of copper = C
Quantity of Gold = G.

From the above mentioned formula, C*(15-9) = G*(19-15)
So It Goes
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