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ratio of triangles

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by cmr209 » Sun Aug 16, 2009 1:28 am
Image

In the rectangular coordinate system above, the area ∆PQR is what fraction of the area of ∆LMN?

A 1/9

B 1/8

C 1/6

D 1/5

E 1/3

Stuck on this one.
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Re: ratio of triangles

by Morgoth » Sun Aug 16, 2009 3:15 am
Base of ∆PQR = 10-6 = 4 [only look at the values of x axis of points P & R]
Height of ∆PQR = 4 [look at the value of y axis of point Q]

Area of ∆PQR = 1/2 * 4 * 4 = 8

Similarly, you can calculate the area of ∆LMN

Area of ∆LMN = 1/2 * 12 * 12 = 72

Fraction = 8/72 = 1/9

Hope this helps.
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by cmr209 » Sun Aug 16, 2009 11:55 pm
You rock!
Thank you!
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by maaz_gmat » Thu Jul 22, 2010 1:51 pm
you seriously do.. I see this was posted a year ago, and I was stuck on it today.. Thanks Mate !! Cheers!
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by singalong » Fri May 06, 2011 11:06 pm
Solution is so easy and I screwed it up in my prep.
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