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Ratio of teaching assistants

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Re: Ratio of teaching assistants

by dtweah » Mon May 18, 2009 12:46 pm
crackgmat007 wrote:Can someone solve this pls?
Use direct proportion to solve. Use equal sign and drop > temporarily.
TA1/S1= TA2/S2
3/80=5/S2
S2=133(1/3)

You are looking for the maximum. You increase a fraction by either making the denominator smaller or the numerator bigger. Since S in in the denominator, to make 5/133(1/3) as big as possible you have to reduce the denominator. The next biggest whole number from it is 133. If the problem had asked for minimum, 134 would have been your answer, because that would make the fraction smaller.
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by crackgmat007 » Tue May 19, 2009 2:06 pm
If the question were to be like the below, I am guessing the answer would be 134..correct?

"student to teach (instead of teach to student) ratio must always be greater than 80:3"
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