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Ratio + inequality ??

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by hpgmat » Tue Nov 17, 2009 11:12 am
on a certain sight seeing tour, ratio of number of women to children was 5 to 2. what was the unmber of men on the sight seeing tour?

1) ratio of nmber of children to men was 5 to 11
2) the number of women was less than 30
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Source: — Data Sufficiency |
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by carllecat » Tue Nov 17, 2009 11:57 am
hpgmat wrote:on a certain sight seeing tour, ratio of number of women to children was 5 to 2. what was the unmber of men on the sight seeing tour?

1) ratio of nmber of children to men was 5 to 11
2) the number of women was less than 30
The ratio Women / Children is 5/2 and we are looking for the number of men on the tour.

1) Men / Chilren is 5 / 11 - This ratio compared with the other ratio does not help to find the total number of men.
2) It would be possible to find the number of men if the number of women was fix and not less or more than... In that case, the less than is hyphothetical and cannot help us to determine how many men were on the tour.

Answer E???
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by palvarez » Tue Nov 17, 2009 11:58 am
1. C:M = 5:11, and W:C = 5:2
W:C:M = 25:10:22 Insuff
2. W < 30 Insuff

Combined, sufficient: W = 25
M = 22
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by carllecat » Tue Nov 17, 2009 12:16 pm
palvarez wrote:1. C:M = 5:11, and W:C = 5:2
W:C:M = 25:10:22 Insuff
2. W < 30 Insuff

Combined, sufficient: W = 25
M = 22
Not sure I get the W:C:M part and the combined one too.
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by hpgmat » Tue Nov 17, 2009 12:24 pm
carllecat wrote:
palvarez wrote:1. C:M = 5:11, and W:C = 5:2
W:C:M = 25:10:22 Insuff
2. W < 30 Insuff

Combined, sufficient: W = 25
M = 22
Not sure I get the W:C:M part and the combined one too.
HE HAS MULTIPLIED FIRST RATIO BY 2 AND THE SECOND RATIO BY 5

WE GET C:M EQUAL TO 10:22
AND W:C EQUAL TO 25:10
NOW WE COMBINE BOTH RATIOS ( 10 IS COMMON)
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by carllecat » Tue Nov 17, 2009 1:52 pm
hpgmat wrote:
carllecat wrote:
palvarez wrote:1. C:M = 5:11, and W:C = 5:2
W:C:M = 25:10:22 Insuff
2. W < 30 Insuff

Combined, sufficient: W = 25
M = 22
Not sure I get the W:C:M part and the combined one too.
HE HAS MULTIPLIED FIRST RATIO BY 2 AND THE SECOND RATIO BY 5

WE GET C:M EQUAL TO 10:22
AND W:C EQUAL TO 25:10
NOW WE COMBINE BOTH RATIOS ( 10 IS COMMON)

Then why is the answer C and not A? Does it really matter that W < 30?
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by hpgmat » Tue Nov 17, 2009 2:14 pm
carllecat wrote:
hpgmat wrote:
carllecat wrote:
palvarez wrote:1. C:M = 5:11, and W:C = 5:2
W:C:M = 25:10:22 Insuff
2. W < 30 Insuff

Combined, sufficient: W = 25
M = 22
Not sure I get the W:C:M part and the combined one too.
HE HAS MULTIPLIED FIRST RATIO BY 2 AND THE SECOND RATIO BY 5

WE GET C:M EQUAL TO 10:22
AND W:C EQUAL TO 25:10
NOW WE COMBINE BOTH RATIOS ( 10 IS COMMON)

Then why is the answer C and not A? Does it really matter that W < 30?
YES THAT PUTS A CONSTRAINT ON IT IF W > 30 ANND LETS ASSUME IF IT WAS 50 THEN NUMBER OF MEN WOULD BE 44 OR IF IT WAS 100 , THEN NUMBER OF MEN WOULD BE 88. KNOWING W < 30 THERE IS ONLY ONE CONDITION WHICH SATISFIES THE RATIO SINCE WE CAN NOT HAVE FRACTIONS AS NUMBER OF PEOPLE ( ONLY INTEGERS COUNT NUMBER OF PEOPLE)
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