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by drnt » Fri Aug 14, 2009 2:36 am
a man has to build a house in 60days for whichhe has 45men.aafter 40days he found it gtn delayed so got 30 more men.he finished job 5 days ahead of schedule.
how many days hwould he hve been behind had he not employd additinl men?
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Answer

by kalyankumar.new » Sat Aug 15, 2009 8:40 am
Let the total no days to require to build the house with 45 men be X.
first 40 days, 45 men worked, so the total work done is 40*45
the job is finished 5 days ahead of 60 days, nothing but 60-5=55 days

so for 15 days 45+30 = 75 men worked.

Total work done =(40*45) + (15*75) = 45 men worked for X days,
45*X = (40*45) + (15*75)
solve for x, X will be 65. that means 45 men would have completed the job in 65 days. so 5 days more than planned.

Regards,
Kalyan.
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