Rates SIM Motion

Let C(l) - represent the larger gear & C(s) - represent the smaller gear.

Given, both the gears turn at the same rate. Lets assume the rate is 96cms/min. From this we know:

C(l) - covers 96pi cms in a min (which is 1 revolution clockwise)
C(s) - covers 96pi cms in a min (which is 4 revolutions anti-clockwise)

From this we know that in a min the notches meet 4 times in one revolution of the larger gear.

This is how far I could get On the D day I might guess an answer for this type of a question.

Tricky one, but I figured it out. Here is how I did it:

First, the circumferences of the circles are 24pi and 96pi, for the small and big circles respectively. When the notch meets for the first time it will create the same angle with respect to the starting point on each of the circles. Call that angle x. Since, as the previous post mentions, the smaller circle rotates 4 times in each of the bigger circle's rotations, this meeting will take place in the upper right quadrant of the circle (the small one will not yet have finished one full rotation, so the bigger one will not yet have finished one quarter of a rotation), which helps for visualization.

At the meeting point, the bigger circle will have traveled (x/360)*96pi centimeters. The smaller circle, whose angle of travel is (360-x), has traveled ((360-x)/360)*24pi - don't forget it traveled counterclockwise. Since the rate and the time of travel is the same (they started at the same time and they met, obviously, at the same time), these distances are equal as well. So you set up the equation:

(x/360)*96pi=((360-x)/360)*24pi ---> x=72.

If x=72, that means that the bigger circle has traveled (72/360)*96pi centimeters, or (96/5)pi, or 19.2 pi. This is after the first meeting of the two notches. Simply double this to find the distance traveled after 2 meetings. The answer, then, is 38.4 pi. Does this look alright?

It is indeed tricky..but well solved. I had a slightly different approach:

To find x (angle at which the two meet),

At angle x, the angle for the smaller gear would be (360 - 4*x)
Since these 2 have to be equal when the two gears meet,
x=360-4x
=> x = 72 degrees

Therefore, distance travelled by larger gear when they first meet would be (72/360)*2*pi*48
Multiple this no. by 2 to get the answer: 38.4pi