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by karthikpandian19 » Mon Dec 26, 2011 3:28 am
Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many kilometers per hour did Tammy walk on the second day?


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by rijul007 » Mon Dec 26, 2011 4:29 am
karthikpandian19 wrote:Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many kilometers per hour did Tammy walk on the second day?


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3.5
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4.5
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Hours walked on first day = 8hrs
Hours walked on second day = 6 hrs

speed on the first day = x km/hr
speed on the second day = (x+ 1/2) km/hr

Total distance = 8x + 6(2x+1)/2
52 = 8x + 6x + 3 = 14x + 3
x = 49/14 = 7/2 = 3.5 km/hr

Avg speed on the second day = x+0.5 = 4km/hr

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by karthikpandian19 » Mon Dec 26, 2011 5:31 am
Your approach made this problem look so simple....thanks
rijul007 wrote:
karthikpandian19 wrote:Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many kilometers per hour did Tammy walk on the second day?


3
3.5
4
4.5
6
Hours walked on first day = 8hrs
Hours walked on second day = 6 hrs

speed on the first day = x km/hr
speed on the second day = (x+ 1/2) km/hr

Total distance = 8x + 6(2x+1)/2
52 = 8x + 6x + 3 = 14x + 3
x = 49/14 = 7/2 = 3.5 km/hr

Avg speed on the second day = x+0.5 = 4km/hr

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by ronnie1985 » Mon Dec 26, 2011 9:16 pm
x km in first day.
x/14+0.5 km/h is speed on second day.
x+12*(x/14+0.5) = 52
x = 46*7/13 = 3.5
Ans = 4
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by karthikpandian19 » Mon Dec 26, 2011 11:42 pm
How is 12 multiplied in the 3rd line of ur explanation
ronnie1985 wrote:x km in first day.
x/14+0.5 km/h is speed on second day.
x+12*(x/14+0.5) = 52
x = 46*7/13 = 3.5
Ans = 4
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by karthikpandian19 » Tue Dec 27, 2011 9:33 pm
OA is C (4)
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