firstly convert 36 mins to hours 1/2 + 1/10=6/10=3/5 hours is the same as 36 mints

speed chef --> 1/8
speed novice --> 1/12

since both are combined in equal numbers, just tale combined speed (rather easy than if it were diff. coeff.) 1/8+1/12=5/24
x is the number of chefs or noives and find the reciprocal of (1+3/5) or 1h.36 mints since speed=1//time
(5/24)*x=5/8, 5x/24=5/8, 5x=24*5/8, x=24/8=3

we need 3 chefs (the same number of novices are req.)

b

karthikpandian19 wrote:On a wedding catering service, An experienced chef can prepare a service for a wedding in 8 hours while an novice chef would finish the preparations in 12 hours.

If the catering service employs the same number of novice and experienced chefs, then how many chefs would it take to prepare a wedding service in 1 hour and 36 minutes?

2
3
4
6
8

@pemdas.....

It should be 6 Chefs (3 Chefs + 3 Novice)

24/5 hrs with 2 chefs (1 chef + 1 novice), so 8/5 hrs with ??? Chefs

= (24/5)/(8/5) * 2

= 6

pemdas wrote:firstly convert 36 mins to hours 1/2 + 1/10=6/10=3/5 hours is the same as 36 mints

speed chef --> 1/8
speed novice --> 1/12

since both are combined in equal numbers, just tale combined speed (rather easy than if it were diff. coeff.) 1/8+1/12=5/24
x is the number of chefs or noives and find the reciprocal of (1+3/5) or 1h.36 mints since speed=1//time
(5/24)*x=5/8, 5x/24=5/8, 5x=24*5/8, x=24/8=3

we need 3 chefs (the same number of novices are req.)

b

karthikpandian19 wrote:On a wedding catering service, An experienced chef can prepare a service for a wedding in 8 hours while an novice chef would finish the preparations in 12 hours.

If the catering service employs the same number of novice and experienced chefs, then how many chefs would it take to prepare a wedding service in 1 hour and 36 minutes?

2
3
4
6
8

I knew this is simple, but i messed up with the Rate / work / time

Can you explain with formula approach for Rate/work/time

Anurag@Gurome wrote:

karthikpandian19 wrote:On a wedding catering service, An experienced chef can prepare a service for a wedding in 8 hours while an novice chef would finish the preparations in 12 hours.

If the catering service employs the same number of novice and experienced chefs, then how many chefs would it take to prepare a wedding service in 1 hour and 36 minutes?

2
3
4
6
8

Time taken by experienced chef = 8 hours
Time taken by novice chef = 12 hours

Let us assume that the catering service employs X novice and experienced chefs.
1 hr 36 mins = 1 36/60 = 1 3/5 = 8/5
Then, 1/(8/5)= X(1/8 + 1/12)
5/8 = X(5/24)
1 = X/3
X = 3
Therefore, total number of chefs required = 3 + 3 = 6

The correct answer is D.

I posted a solution here:

https://www.beatthegmat.com/ps-caterers-t89876.html

pemdas wrote:firstly convert 36 mins to hours 1/2 + 1/10=6/10=3/5 hours is the same as 36 mints

speed chef --> 1/8
speed novice --> 1/12

since both are combined in equal numbers, just tale combined speed (rather easy than if it were diff. coeff.) 1/8+1/12=5/24
x is the number of chefs or noives and find the reciprocal of (1+3/5) or 1h.36 mints since speed=1//time
(5/24)*x=5/8, 5x/24=5/8, 5x=24*5/8, x=24/8=3

we need 3 chefs (the same number of novices are req.)

b

karthikpandian19 wrote:On a wedding catering service, An experienced chef can prepare a service for a wedding in 8 hours while an novice chef would finish the preparations in 12 hours.

If the catering service employs the same number of novice and experienced chefs, then how many chefs would it take to prepare a wedding service in 1 hour and 36 minutes?

2
3
4
6
8

I think 6. 3 novice & 3 experienced.

user123321

karthikpandian19 wrote:On a wedding catering service, An experienced chef can prepare a service for a wedding in 8 hours while an novice chef would finish the preparations in 12 hours.

If the catering service employs the same number of novice and experienced chefs, then how many chefs would it take to prepare a wedding service in 1 hour and 36 minutes?

2
3
4
6
8

Let the total work be 96 units....

Now , efficiency of the chief is 12 units/hr

Efficiency of the inexperienced chief is 8units/hr


Say " a " no of experienced and in experienced chiefs r recruited..

So , the work done by them in 1 hour is 20a units...

Hence , they prepare 20 units in 60 minutes...


Now the time given is 96 minutes...

In 60 mints 20 units is produced

In 1 mint 1/3 units is produced

Hence in 96 mints ( 1/3 )96 => 32 units is produced...


Now , we have considered the entire Cake as 96 units , so the total no of people required is 96 / 32 => 3


hence we require 3 3 novice & 3 experienced chiefs...

Combined speed = 1/8+1/12 = 5/24 hr^-1
If x set of novices and chef required then x*5/24 = 5/8 = > x = 3

OA is 6