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by smclean23 » Wed Jul 30, 2008 4:18 pm
If N= (2^2)(3^4)(5^6) , the value of which of the following products is greater than sq. rt. of n ?
I. (2)(3^3)(5^2)
II. (2)(3)(5^4)
III. (2^2)(3^2)(5^3)

(A) None
(B) I only
(C) II only
(D) III only
(E) II and III




Answer is E
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by Vignesh.4384 » Wed Jul 30, 2008 8:11 pm
SQRT of N = 2 * (3^2)* (5^3).

so the answer has to be E
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by parallel_chase » Thu Jul 31, 2008 1:35 am
The answer is indeed E. sqrtN = 2*3^2*5^3

Option III (2^2)(3^2)(5^3) will always be greater.

Option II (2)(3)(5^4) will always be greater.

Hence E.
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