32)

Avg = Sum /n

17.5 = 6x+15/6

So D is sufficient

Combining 1 and 2 all we know is the information of
top 4 countires > X and the share of X

We dont have information about the rest of the 15 countries

Hence E

Here the woding of the question us the trick ..


It says one kind of C and D ...none of the statements mentions anything about the "kind" purchased

Hence E

0.abc.............a - TENTH DIGIT , b - HUNDREDTHS , c - THOUSANDTHS..

IS 100th DIGIT OG D > 5

1) TENTH DIGIT OF 10D = 7 , LET D = 0.472, => 10D = 4.72 , SO TENTHS DIGIT OF 10D = 7 , AND HUNDREDTHS DIGIT OG D = 7 >5

SO IN ALL D CASE WE HAVE 100TH DIGIT OF D = 7 WHICH IS > 5 ....

2) 1000TH DIGIT OF D/10 = 7 THIS CASE IS SAME AS (1)

TAKE D = 0.472 => D/10 = 0.0472 , SO 1000TH DIGIT OF D/10 = 7 AND 100th digit of D = 7 WHICH IS > 5

Thanks.

For the average question, how do you know stmt 1 is sufficient? Do you just determine that if 20 is the greatest, then the smallest number is 20-5?

Or is that after using stmt 2 to figure out the answer, you realize that in stmt 1, 20-5 also leads to the same answer? hence sufficient.

xcise_science, I agree with Sujoysolanki! Look in the Qs & stmt - 1, it is directly saying that the largest of the consecutive numbers is 20. So we can easily go for 20 - 5. It is clearly mentioned in the Qs.