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by Anamaiy » Thu Jun 02, 2011 3:58 am
A batch of cookies was divided among three tins: 2/3 of all the cookies were placed in either green tin or blue tin, the rest were placed in red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin.
a). 15/2
b). 9/4
c). 5/9
d). 7/5
e). 9/7

Please explain your answers. Thanks
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by cans » Thu Jun 02, 2011 4:06 am
let there be total 12 cookies. (I chose 12 because of the 3&4 in denominator (lcm of 3&4 is 12))
1/4of 12 in blue => blue tin has 3 cookies
2/3 of 12 in either green or blue.8 in either green or blue
We know blue has 3 cookies, thus 5 in green
also last sentence says that 1/4 (ie 3 cookies were placed in blue) and thus remaining 9 were placed in others (9=12-3)
also out of 9, 5 were placed in green
thus fraction = 5/9
IMO C
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by Anamaiy » Thu Jun 02, 2011 4:10 am
cans wrote:let there be total 12 cookies. (I chose 12 because of the 3&4 in denominator (lcm of 3&4 is 12))
1/4of 12 in blue => blue tin has 3 cookies
2/3 of 12 in either green or blue.8 in either green or blue
We know blue has 3 cookies, thus 5 in green
also last sentence says that 1/4 (ie 3 cookies were placed in blue) and thus remaining 9 were placed in others (9=12-3)
also out of 9, 5 were placed in green
thus fraction = 5/9
IMO C
so basically the question asked for (green/{red+green}) thanks
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by cans » Thu Jun 02, 2011 4:27 am
Yup.. that's the basic question :)
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by gmatjeet » Fri Jun 03, 2011 6:29 am
A batch of cookies was divided among three tins: 2/3 of all the cookies were placed in either green tin or blue tin, the rest were placed in red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin.
a). 15/2
b). 9/4
c). 5/9
d). 7/5
e). 9/7

Total cookies = x
-> the rest were placed in RED tin. -> x/3
-> Green + Blue = 2x/3
-> Blue = x/4
-> Green = 2x/3-x/4 = 5x/12

Green/(Blue+ Red) = 5x/12 / 7x/12 = 5/7

Answer doesnt match..cn smone verify the question?

@ cans: u have missed considering the Red tin
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by sunilramu » Fri Jun 03, 2011 7:47 am
gmatjeet wrote:A batch of cookies was divided among three tins: 2/3 of all the cookies were placed in either green tin or blue tin, the rest were placed in red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin.
a). 15/2
b). 9/4
c). 5/9
d). 7/5
e). 9/7

Total cookies = x
-> the rest were placed in RED tin. -> x/3
-> Green + Blue = 2x/3
-> Blue = x/4
-> Green = 2x/3-x/4 = 5x/12

Green/(Blue+ Red) = 5x/12 / 7x/12 = 5/7
Green/(Green+ Red) = 5x/12 / 9x/12 = 5/9

Answer doesnt match..cn smone verify the question?

@ cans: u have missed considering the Red tin
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by cans » Fri Jun 03, 2011 8:36 am
gmatjeet wrote:A batch of cookies was divided among three tins: 2/3 of all the cookies were placed in either green tin or blue tin, the rest were placed in red tin. If 1/4 of all the cookies were placed in the blue tin, what fraction of the cookies that were placed in the other tins were placed in the green tin.
a). 15/2
b). 9/4
c). 5/9
d). 7/5
e). 9/7

Total cookies = x
-> the rest were placed in RED tin. -> x/3
-> Green + Blue = 2x/3
-> Blue = x/4
-> Green = 2x/3-x/4 = 5x/12

Green/(Blue+ Red) = 5x/12 / 7x/12 = 5/7

Answer doesnt match..cn smone verify the question?

@ cans: u have missed considering the Red tin
@gmatjeet: read the line in green carefully.
1/4 placed in blue and what fraction of others were placed in green tin.
So we have to find green/(green+red)
1/4 placed in blue, thus 3/4 placed in other (green or red). now we have to find fraction of green among these 3/4
Hope it's clear.. :)
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Cans!!
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