Could anyone offer a quick way of solving this?
[(8^2)(3^3)(2^4)]/96^2
1) 3
2) 6
3) 9
4) 12
5) 18
Thanks in advance!
[(8^2)(3^3)(2^4)]/96^2
1) 3
2) 6
3) 9
4) 12
5) 18
Thanks in advance!
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= (2^3)^2 (3^3) (2^4) / (6^2) (16^2)awilhelm wrote:Could anyone offer a quick way of solving this?
[(8^2)(3^3)(2^4)]/96^2
1) 3
2) 6
3) 9
4) 12
5) 18
Thanks in advance!
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