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i guess angles BAO=BOA=x & OBC=OCB=y; and x might not be equal to y (do correct me if m wrong here)muzali wrote:AB=OC (given) and OC=OB (since both are radii of the semicircle)
=> AB=OC=OB
=>angles BAO=BOA=OBC=OCB=x (angles opposite equal sides)
We need to find x.
the answer is D, however OBC=OCB= 2x ... instead of =xmuzali wrote:AB=OC (given) and OC=OB (since both are radii of the semicircle)
=> AB=OC=OB
=>angles BAO=BOA=OBC=OCB=x (angles opposite equal sides)
We need to find x.
1. COD is 60
BOA+BOC+COD=180 (supplementary angles)
x+(180-2x)+60=180
We can find x, so STM 1 is suff.
2.BCO=40
i.e. x =40
STM 2 is suff.
So answer is D
yep x=20ch0719 wrote:the answer is D, however OBC=OCB= 2x ... instead of =xmuzali wrote:AB=OC (given) and OC=OB (since both are radii of the semicircle)
=> AB=OC=OB
=>angles BAO=BOA=OBC=OCB=x (angles opposite equal sides)
We need to find x.
1. COD is 60
BOA+BOC+COD=180 (supplementary angles)
x+(180-2x)+60=180
We can find x, so STM 1 is suff.
2.BCO=40
i.e. x =40
STM 2 is suff.
So answer is D
so STM1 should be:
x+(180-4x)+60=180x
and x=20 imo
STM2 is correct