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Question about the length and width of my next widescreen TV

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by tnis0612 » Tue Nov 18, 2008 1:54 pm
This question woudlnt be on the GMAT because of the fact that you can't use a calculator but it was something I was trying to figure out the other day and I was able to solve it from things I learned studying. How would everyone else solve this (just to make sure I did it correctly)?

A television measures 60in diagonally. If the ratio of length to width is 16:9, what is the length and the width?
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by mals24 » Tue Nov 18, 2008 2:14 pm
l:w = 16:9

l/w = 16/9

l = 16w/9

Using Pythagoras theorem

l^2+w^2 = 60^2

(16w)^2/81+w^2 = 3600

Youll get w = 865

length = 1537
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Re: Question about the length and width of my next widescree

by logitech » Tue Nov 18, 2008 2:51 pm
See Mals24's explanation!
Last edited by logitech on Tue Nov 18, 2008 3:04 pm, edited 1 time in total.
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by mals24 » Tue Nov 18, 2008 2:56 pm
@ logitech

Just a little correction

9-16-25 is not the same as 3-4-5

9-12-15 or 15-20-25 is the same as 3-4-5

:)
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by logitech » Tue Nov 18, 2008 3:03 pm
mals24 wrote:@ logitech

Just a little correction

9-16-25 is not the same as 3-4-5

9-12-15 or 15-20-25 is the same as 3-4-5

:)
Well it is not a little correction actually. What I explained did not make any sense ;-)

9-16-25 is not the same as 3-4-5 :oops:

This is what I call a "SILLY" mistake.
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Re: Question about the length and width of my next widescree

by logitech » Tue Nov 18, 2008 3:04 pm
SILLY MISTAKE! :shock:
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by mals24 » Tue Nov 18, 2008 3:06 pm
Its ok no mistake is silly because you learn a lot from them.
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by dmateer25 » Tue Nov 18, 2008 3:18 pm
mals24 wrote:l:w = 16:9

l/w = 16/9

l = 16w/9

Using Pythagoras theorem

l^2+w^2 = 60^2

(16w)^2/81+w^2 = 3600

Youll get w = 865

length = 1537
Shouldn't the diagonal be the longest?

(16w)^2/81+w^2 = 3600

(16w/9)(16w/9) =(256(w^2)/81) + w^2 = 3600

256w^2/81 + 81w^2/81 = 3600
337w^2/81 = 3600
337w^2 = 291600
w^2 = 865
w=29.4

l= 52.26
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