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Question 6 (nov. 15th)

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by bacali » Sat Nov 15, 2008 4:52 pm
Each person attending a fund-raising party for a certain club was charged the same admission fee. How many people attended the party?

1) If the admission fee had been $0.75 less and 100 more people attended, the club would have received the same amount in admission fees.

2) If the admission fee had been $1.50 more and 100 fewer people had attended, the club would have received the same amount in admission fees.

OA: [spoiler] C

[/spoiler]
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Source: — Data Sufficiency |
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by cramya » Sat Nov 15, 2008 5:12 pm
Given info in the question stem:

Let f be the fee collected and x be the number of people who attended

Total amount collected = fx

We need to find x

Stmt I) (less fee collected more people attended)

(f-.75)(x+100) = fx (1)

1 eqn 2 variables INSUFF


Stmt II

Very similar to statement I but this time more fee collected less people attended

(f+1.5)(x-100) = fx (2)

1 eqn 2 variables INSUFF

Statement I and II together

2 variables (f and x) 2 equations we can solve for x (fx cancels out in both equation if u look at (1) and (2)

SUFF

C)
Last edited by cramya on Sat Nov 15, 2008 5:13 pm, edited 1 time in total.
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by dmateer25 » Sat Nov 15, 2008 5:12 pm
Stmt 1

x = fee
y=people

xy=(y+100)(x-.75) (i)

Insuff only 1 equation

Stmt 2

xy=(y-100)(x-1.5)

Insuff only 1 equation

Together

You have 2 equations and 2 variable. Together they are sufficient
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by dmateer25 » Sat Nov 15, 2008 5:14 pm
cramya wrote:Given info in the question stem:

Let f be the fee collected and x be the number of people who attended

Total amount collected = fx

We need to find x

Stmt I) (less fee collected more people attended)

(f-.75)(x+100) = fx (1)

1 eqn 2 variable

INSUFF

Stmt II

Very similar to statemtn one but this time more fee collected less people attended

(f+1.5)(x-100) = fx (2)

2 variables one eqn INSUFF

Statement I and II together

2 variables (f and x) 2 equations we can solve for x (fx cancels out in both equation if u look at (1) and (2)

SUFF

C)
That's twice today! You type too fast!

Nice work again Cramya!
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by Tryingmybest » Sun Nov 16, 2008 8:40 am
This might sound silly . But need your help in solving this

(f-.75)(x+100)=(f+1.5)(x-100)
fx+100f-.75x-75=fx-100f+1.5x-150

200f-2.25x+75=0

Now how do I solve for X ??

to me its E
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