Each person attending a fund-raising party for a certain club was charged the same admission fee. How many people attended the party? 1) If the admission fee had been $0.75 less and 100 more people attended, the club would have received the same amount in admission fees. 2) If the admission fee had been $1.50 more and 100 fewer people had attended, the club would have received the same amount in admission fees. OA: [spoiler] C [/spoiler]

Given info in the question stem: Let f be the fee collected and x be the number of people who attended Total amount collected = fx We need to find x Stmt I) (less fee collected more people attended) (f-.75)(x+100) = fx (1) 1 eqn 2 variables INSUFF Stmt II Very similar to statement I but this time more fee collected less people attended (f+1.5)(x-100) = fx (2) 1 eqn 2 variables INSUFF Statement I and II together 2 variables (f and x) 2 equations we can solve for x (fx cancels out in both equation if u look at (1) and (2) SUFF C)

Stmt 1 x = fee y=people xy=(y+100)(x-.75) (i) Insuff only 1 equation Stmt 2 xy=(y-100)(x-1.5) Insuff only 1 equation Together You have 2 equations and 2 variable. Together they are sufficient

cramya wrote:Given info in the question stem: Let f be the fee collected and x be the number of people who attended Total amount collected = fx We need to find x Stmt I) (less fee collected more people attended) (f-.75)(x+100) = fx (1) 1 eqn 2 variable INSUFF Stmt II Very similar to statemtn one but this time more fee collected less people attended (f+1.5)(x-100) = fx (2) 2 variables one eqn INSUFF Statement I and II together 2 variables (f and x) 2 equations we can solve for x (fx cancels out in both equation if u look at (1) and (2) SUFF C) That's twice today! You type too fast! Nice work again Cramya!

This might sound silly . But need your help in solving this (f-.75)(x+100)=(f+1.5)(x-100) fx+100f-.75x-75=fx-100f+1.5x-150 200f-2.25x+75=0 Now how do I solve for X ?? to me its E

Question 6 (nov. 15th) - The Beat The GMAT Forum - Expert GMAT Help & MBA Admissions Advice

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