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Que: The trader first decreased the selling price of a car by 30 percent and then increased by 30 percent.....

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by Max@Math Revolution » Fri Jul 16, 2021 8:59 am

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Que: The trader first decreased the selling price of a car by 30 percent and then increased by 30 percent. Which of the following represents the final percent change in the selling price of the bicycle?

(A) 9% less
(B) 0%
(C) 9% more
(D) 91% less
(E) 91% more
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Re: Que: The trader first decreased the selling price of a car by 30 percent and then increased by 30 percent.....

by Max@Math Revolution » Sat Jul 17, 2021 9:19 pm
Solution: Let us apply the IVY approach to solve the question. As we are dealing with percentage, then let the original price of a car be $100.

Price after price reduced by 30%: (100 - 30)% of $100

=> \(\frac{70}{100}\cdot$100=$70\)

Price after the new price increased by 30%: (100 + 30)% of $70

=> \(\frac{130}{100}\cdot$70=$91\)

As the base price is $100, the final price would be 91% of the base price.

Since Percent change = \(\frac{After\ -\ Before}{Before}\cdot100\%\) and $100 (Before) and $91 (After),

We get Percent change = \(\frac{91\ -\ 100}{100}\cdot100\%=\frac{-9}{100}\cdot100\%=-9\%\)

Therefore, A is the correct answer.

Answer A
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