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Quadrilateral ABCD is a parallelogram.

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by Max@Math Revolution » Thu Jun 11, 2020 12:33 am

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[GMAT math practice question]

Quadrilateral ABCD is a parallelogram. Point E is on line BC, line DE bisects \(<\) D, and AF is perpendicular to DE. If \(<\) C = 115, what is the measure of the angle \(<\) BAF?
6.11PS.png
A. 32.5
B. 45.5
C. 57.5
D. 58
E. 59.5
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Re: Quadrilateral ABCD is a parallelogram.

by Max@Math Revolution » Sun Jun 14, 2020 5:49 pm
=>

∠B = ∠D = 180° - 115° = 65°.
∠ADF = ∠EDC = (1/2) ∠D = (1/2)65° = 32.5°.
∠BAF = ∠A - ∠DAF = 115° – (90° - 32.5°) = 57.5°

Therefore, C is the answer.
Answer: C
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