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Quadratic

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
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by cans » Sat Jun 11, 2011 5:36 am
x = -5 + ( 45 +4k - k^2 )0.5 >0
35 + 4k - k^2 >0
or k^2 - 4k - 35 <0
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by Tani » Mon Jun 13, 2011 7:50 am
using the quadratic equation, for the expression k^2 - 4K - 35 to equal zero, k would have to equal 2+ Sqrt(39). That would give you a value either slightly less than -4 or slightly more than +8. The values that make x positive will be in that range. Ignoring the negative integers and zero, you get 1,2,3,4,5,6,7, and 8. Answer 8.
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