dtweah wrote:A positive integer with exactly four positive factors is called "quadly".
If m is the least n for which each of n, n + 1, and n + 2 is quadly, then which of the following is odd?

A. m+1

B. m-11

C. m-6

D. 3m-1

E. 5m+1

We can do this lickety split by working with the answer choices and pretty much ignoring the question.

Here's all we need to know from the question stem: m is a fixed integer.

If m is even, then a, b, d and e will all be odd. Can we have 4 correct answers to a question? NO! Therefore, m cannot be even.

With m being odd, only (C) is odd... choose (C)!